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27x^2-168x+36=0
a = 27; b = -168; c = +36;
Δ = b2-4ac
Δ = -1682-4·27·36
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{24336}=156$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-168)-156}{2*27}=\frac{12}{54} =2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-168)+156}{2*27}=\frac{324}{54} =6 $
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